Mercurial > hg
view tests/test-lrucachedict.py @ 52293:77b38c86915d
ci: add a small script one can run to purge older pipeline
We have over ten thousands old pipeline that take a huge space and that I
suspect to be the source of some slowdown in merge request.
However it seems that the only way to clear them is manually and through the
API, so lets do it.
The script was run today.
author | Pierre-Yves David <pierre-yves.david@octobus.net> |
---|---|
date | Tue, 12 Nov 2024 12:45:23 +0100 |
parents | 6000f5b25c9b |
children |
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import unittest import silenttestrunner from mercurial import util class testlrucachedict(unittest.TestCase): def testsimple(self): d = util.lrucachedict(4) self.assertEqual(d.capacity, 4) d.insert('a', 'va', cost=2) d['b'] = 'vb' d['c'] = 'vc' d.insert('d', 'vd', cost=42) self.assertEqual(d['a'], 'va') self.assertEqual(d['b'], 'vb') self.assertEqual(d['c'], 'vc') self.assertEqual(d['d'], 'vd') self.assertEqual(d.totalcost, 44) # 'a' should be dropped because it was least recently used. d['e'] = 've' self.assertNotIn('a', d) self.assertIsNone(d.get('a')) self.assertEqual(d.totalcost, 42) self.assertEqual(d['b'], 'vb') self.assertEqual(d['c'], 'vc') self.assertEqual(d['d'], 'vd') self.assertEqual(d['e'], 've') # Replacing item with different cost adjusts totalcost. d.insert('e', 've', cost=4) self.assertEqual(d.totalcost, 46) # Touch entries in some order (both get and set). d['e'] d['c'] = 'vc2' d['d'] d['b'] = 'vb2' # 'e' should be dropped now d['f'] = 'vf' self.assertNotIn('e', d) self.assertEqual(d['b'], 'vb2') self.assertEqual(d['c'], 'vc2') self.assertEqual(d['d'], 'vd') self.assertEqual(d['f'], 'vf') d.clear() for key in ('a', 'b', 'c', 'd', 'e', 'f'): self.assertNotIn(key, d) def testunfull(self): d = util.lrucachedict(4) d['a'] = 1 d['b'] = 2 d['a'] d['b'] for key in ('a', 'b'): self.assertIn(key, d) def testget(self): d = util.lrucachedict(4) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' self.assertIsNone(d.get('missing')) self.assertEqual(list(d), ['c', 'b', 'a']) self.assertEqual(d.get('a'), 'va') self.assertEqual(list(d), ['a', 'c', 'b']) def testpeek(self): d = util.lrucachedict(4) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' with self.assertRaises(KeyError): d.peek('missing') self.assertEqual(list(d), ['c', 'b', 'a']) self.assertIsNone(d.peek('missing', None)) self.assertEqual(list(d), ['c', 'b', 'a']) self.assertEqual(d.peek('a'), 'va') self.assertEqual(list(d), ['c', 'b', 'a']) def testpop(self): d = util.lrucachedict(4) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' with self.assertRaises(KeyError): d.pop('missing') self.assertEqual(list(d), ['c', 'b', 'a']) self.assertIsNone(d.pop('missing', None)) self.assertEqual(list(d), ['c', 'b', 'a']) self.assertEqual(d.pop('b'), 'vb') self.assertEqual(list(d), ['c', 'a']) def testcopypartial(self): d = util.lrucachedict(4) d.insert('a', 'va', cost=4) d.insert('b', 'vb', cost=2) dc = d.copy() self.assertEqual(len(dc), 2) self.assertEqual(dc.totalcost, 6) for key in ('a', 'b'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) self.assertEqual(len(d), 2) for key in ('a', 'b'): self.assertIn(key, d) self.assertEqual(d[key], 'v%s' % key) d['c'] = 'vc' del d['b'] self.assertEqual(d.totalcost, 4) dc = d.copy() self.assertEqual(len(dc), 2) self.assertEqual(dc.totalcost, 4) for key in ('a', 'c'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) def testcopyempty(self): d = util.lrucachedict(4) dc = d.copy() self.assertEqual(len(dc), 0) def testcopyfull(self): d = util.lrucachedict(4) d.insert('a', 'va', cost=42) d['b'] = 'vb' d['c'] = 'vc' d['d'] = 'vd' dc = d.copy() for key in ('a', 'b', 'c', 'd'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) self.assertEqual(d.totalcost, 42) self.assertEqual(dc.totalcost, 42) # 'a' should be dropped because it was least recently used. dc['e'] = 've' self.assertNotIn('a', dc) for key in ('b', 'c', 'd', 'e'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) self.assertEqual(d.totalcost, 42) self.assertEqual(dc.totalcost, 0) # Contents and order of original dict should remain unchanged. dc['b'] = 'vb_new' self.assertEqual(list(iter(d)), ['d', 'c', 'b', 'a']) for key in ('a', 'b', 'c', 'd'): self.assertEqual(d[key], 'v%s' % key) d = util.lrucachedict(4, maxcost=42) d.insert('a', 'va', cost=5) d.insert('b', 'vb', cost=4) d.insert('c', 'vc', cost=3) dc = d.copy() self.assertEqual(dc.maxcost, 42) self.assertEqual(len(dc), 3) # Max cost can be lowered as part of copy. dc = d.copy(maxcost=10) self.assertEqual(dc.maxcost, 10) self.assertEqual(len(dc), 2) self.assertEqual(dc.totalcost, 7) self.assertIn('b', dc) self.assertIn('c', dc) def testcopydecreasecapacity(self): d = util.lrucachedict(5) d.insert('a', 'va', cost=4) d.insert('b', 'vb', cost=2) d['c'] = 'vc' d['d'] = 'vd' dc = d.copy(2) self.assertEqual(dc.totalcost, 0) for key in ('a', 'b'): self.assertNotIn(key, dc) for key in ('c', 'd'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) dc.insert('e', 've', cost=7) self.assertEqual(dc.totalcost, 7) self.assertNotIn('c', dc) for key in ('d', 'e'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) # Original should remain unchanged. self.assertEqual(d.totalcost, 6) for key in ('a', 'b', 'c', 'd'): self.assertIn(key, d) self.assertEqual(d[key], 'v%s' % key) def testcopyincreasecapacity(self): d = util.lrucachedict(5) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' d['d'] = 'vd' dc = d.copy(6) for key in ('a', 'b', 'c', 'd'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) dc['e'] = 've' dc['f'] = 'vf' for key in ('a', 'b', 'c', 'd', 'e', 'f'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) dc['g'] = 'vg' self.assertNotIn('a', dc) for key in ('b', 'c', 'd', 'e', 'f', 'g'): self.assertIn(key, dc) self.assertEqual(dc[key], 'v%s' % key) # Original should remain unchanged. for key in ('a', 'b', 'c', 'd'): self.assertIn(key, d) self.assertEqual(d[key], 'v%s' % key) def testpopoldest(self): d = util.lrucachedict(4) d.insert('a', 'va', cost=10) d.insert('b', 'vb', cost=5) self.assertEqual(len(d), 2) self.assertEqual(d.popoldest(), ('a', 'va')) self.assertEqual(len(d), 1) self.assertEqual(d.totalcost, 5) self.assertEqual(d.popoldest(), ('b', 'vb')) self.assertEqual(len(d), 0) self.assertEqual(d.totalcost, 0) self.assertIsNone(d.popoldest()) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' d['d'] = 'vd' self.assertEqual(d.popoldest(), ('a', 'va')) self.assertEqual(len(d), 3) for key in ('b', 'c', 'd'): self.assertEqual(d[key], 'v%s' % key) d['a'] = 'va' self.assertEqual(d.popoldest(), ('b', 'vb')) def testmaxcost(self): # Item cost is zero by default. d = util.lrucachedict(6, maxcost=10) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' d['d'] = 'vd' self.assertEqual(len(d), 4) self.assertEqual(d.totalcost, 0) d.clear() # Insertion to exact cost threshold works without eviction. d.insert('a', 'va', cost=6) d.insert('b', 'vb', cost=4) self.assertEqual(len(d), 2) self.assertEqual(d['a'], 'va') self.assertEqual(d['b'], 'vb') # Inserting a new element with 0 cost works. d['c'] = 'vc' self.assertEqual(len(d), 3) # Inserting a new element with cost putting us above high # water mark evicts oldest single item. d.insert('d', 'vd', cost=1) self.assertEqual(len(d), 3) self.assertEqual(d.totalcost, 5) self.assertNotIn('a', d) for key in ('b', 'c', 'd'): self.assertEqual(d[key], 'v%s' % key) # Inserting a new element with enough room for just itself # evicts all items before. d.insert('e', 've', cost=10) self.assertEqual(len(d), 1) self.assertEqual(d.totalcost, 10) self.assertIn('e', d) # Inserting a new element with cost greater than threshold # still retains that item. d.insert('f', 'vf', cost=11) self.assertEqual(len(d), 1) self.assertEqual(d.totalcost, 11) self.assertIn('f', d) # Inserting a new element will evict the last item since it is # too large. d['g'] = 'vg' self.assertEqual(len(d), 1) self.assertEqual(d.totalcost, 0) self.assertIn('g', d) d.clear() d.insert('a', 'va', cost=7) d.insert('b', 'vb', cost=3) self.assertEqual(len(d), 2) # Replacing a value with smaller cost won't result in eviction. d.insert('b', 'vb2', cost=2) self.assertEqual(len(d), 2) # Replacing a value with a higher cost will evict when threshold # exceeded. d.insert('b', 'vb3', cost=4) self.assertEqual(len(d), 1) self.assertNotIn('a', d) def testmaxcostcomplex(self): d = util.lrucachedict(100, maxcost=100) d.insert('a', 'va', cost=9) d.insert('b', 'vb', cost=21) d.insert('c', 'vc', cost=7) d.insert('d', 'vc', cost=50) self.assertEqual(d.totalcost, 87) # Inserting new element should free multiple elements so we hit # low water mark. d.insert('e', 'vd', cost=25) self.assertEqual(len(d), 2) self.assertNotIn('a', d) self.assertNotIn('b', d) self.assertNotIn('c', d) self.assertIn('d', d) self.assertIn('e', d) if __name__ == '__main__': silenttestrunner.main(__name__)