index: don't include nullid in len()
I suspect the reason the nullid is in the index in the last position
is that it lets index[i] for regular revision number, even when index
was just a regular Python list. An alternative solution would have
been to reserve revision number 0 for the null revision. I don't know
why that wasn't done. Now that we have classes backing the index, we
can easily make index[-1] get the nullid without having to put it last
in the list and including it in the len().
This patch just hides the nullid -- it will still be accessible at
index[len(index)].
I realize that this will be annoying when checking out across this
commit for debugging (including bisection).
Differential Revision: https://phab.mercurial-scm.org/D4022
from __future__ import absolute_import
import __builtin__
import os
from mercurial import (
util,
)
def lowerwrap(scope, funcname):
f = getattr(scope, funcname)
def wrap(fname, *args, **kwargs):
d, base = os.path.split(fname)
try:
files = os.listdir(d or '.')
except OSError:
files = []
if base in files:
return f(fname, *args, **kwargs)
for fn in files:
if fn.lower() == base.lower():
return f(os.path.join(d, fn), *args, **kwargs)
return f(fname, *args, **kwargs)
scope.__dict__[funcname] = wrap
def normcase(path):
return path.lower()
os.path.normcase = normcase
for f in 'file open'.split():
lowerwrap(__builtin__, f)
for f in "chmod chown open lstat stat remove unlink".split():
lowerwrap(os, f)
for f in "exists lexists".split():
lowerwrap(os.path, f)
lowerwrap(util, 'posixfile')