view tests/test-lrucachedict.py @ 36975:795eb53f1d3e

rebase: allow in-memory merge of the working copy parent Before this patch and when the rebase involved the working copy parent (and thus the working copy too), we would not do in-memory rebase even if requested to. The in-code comment explains that the reason had something to do with avoiding an extra update, but I don't know which update that refers to. Perhaps an earlier version of the code used to update to the destination before rebasing even if in-memory rebase was requested? That seems to not be done at least since aa660c1203a9 (rebase: do not bail on uncomitted changes if rebasing in-memory, 2017-12-07). To see if this still made it slower, I create a single tiny commit on top of one branch of the mozilla-unified repo (commit a1098c82 to be exact) and rebased it to another branch (commit d4e9a7be). Before this patch that took 11.8s and after this patch it took 8.6s (I only did two runs each, but the timings were very consistent). Differential Revision: https://phab.mercurial-scm.org/D2876
author Martin von Zweigbergk <martinvonz@google.com>
date Thu, 15 Mar 2018 13:19:55 -0700
parents 79add5a4e857
children 067f7d2c7d60
line wrap: on
line source

from __future__ import absolute_import, print_function

from mercurial import (
    util,
)

def printifpresent(d, xs, name='d'):
    for x in xs:
        present = x in d
        print("'%s' in %s: %s" % (x, name, present))
        if present:
            print("%s['%s']: %s" % (name, x, d[x]))

def test_lrucachedict():
    d = util.lrucachedict(4)
    d['a'] = 'va'
    d['b'] = 'vb'
    d['c'] = 'vc'
    d['d'] = 'vd'

    # all of these should be present
    printifpresent(d, ['a', 'b', 'c', 'd'])

    # 'a' should be dropped because it was least recently used
    d['e'] = 've'
    printifpresent(d, ['a', 'b', 'c', 'd', 'e'])

    assert d.get('a') is None
    assert d.get('e') == 've'

    # touch entries in some order (get or set).
    d['e']
    d['c'] = 'vc2'
    d['d']
    d['b'] = 'vb2'

    # 'e' should be dropped now
    d['f'] = 'vf'
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

    d.clear()
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

    # Now test dicts that aren't full.
    d = util.lrucachedict(4)
    d['a'] = 1
    d['b'] = 2
    d['a']
    d['b']
    printifpresent(d, ['a', 'b'])

    # test copy method
    d = util.lrucachedict(4)
    d['a'] = 'va3'
    d['b'] = 'vb3'
    d['c'] = 'vc3'
    d['d'] = 'vd3'

    dc = d.copy()

    # all of these should be present
    print("\nAll of these should be present:")
    printifpresent(dc, ['a', 'b', 'c', 'd'], 'dc')

    # 'a' should be dropped because it was least recently used
    print("\nAll of these except 'a' should be present:")
    dc['e'] = 've3'
    printifpresent(dc, ['a', 'b', 'c', 'd', 'e'], 'dc')

    # contents and order of original dict should remain unchanged
    print("\nThese should be in reverse alphabetical order and read 'v?3':")
    dc['b'] = 'vb3_new'
    for k in list(iter(d)):
        print("d['%s']: %s" % (k, d[k]))

if __name__ == '__main__':
    test_lrucachedict()