view mercurial/dicthelpers.py @ 20291:7d589d923b8a

url: added authuri when login information is requested (issue3209)

When users are using a revset they can get multiple password prompts.
This prompts have no extra information about which password is being requested
so I added the authuri to the prompt to make it recognizable.

As in:
$ hg log -r "outgoing('https://bitbucket.org/mg/test') -
outgoing('https://bitbucket.org/nesneros/test')"
http authorization required
realm: Bitbucket.org HTTP
user: interrupted!

I changed it to describe the url when prompting for password.
As in:
$ hg log -r "outgoing('https://bitbucket.org/mg/test') -
outgoing('https://bitbucket.org/nesneros/test')"
http authorization required for https://bitbucket.org/mg/test
realm: Bitbucket.org HTTP
user: interrupted!

# dicthelpers.py - helper routines for Python dicts
#
# Copyright 2013 Facebook
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.

def diff(d1, d2, default=None):
    '''Return all key-value pairs that are different between d1 and d2.

    This includes keys that are present in one dict but not the other, and
    keys whose values are different. The return value is a dict with values
    being pairs of values from d1 and d2 respectively, and missing values
    treated as default, so if a value is missing from one dict and the same as
    default in the other, it will not be returned.'''
    res = {}
    if d1 is d2:
        # same dict, so diff is empty
        return res

    for k1, v1 in d1.iteritems():
        v2 = d2.get(k1, default)
        if v1 != v2:
            res[k1] = (v1, v2)

    for k2 in d2:
        if k2 not in d1:
            v2 = d2[k2]
            if v2 != default:
                res[k2] = (default, v2)

    return res

def join(d1, d2, default=None):
    '''Return all key-value pairs from both d1 and d2.

    This is akin to an outer join in relational algebra. The return value is a
    dict with values being pairs of values from d1 and d2 respectively, and
    missing values represented as default.'''
    res = {}

    for k1, v1 in d1.iteritems():
        if k1 in d2:
            res[k1] = (v1, d2[k1])
        else:
            res[k1] = (v1, default)

    if d1 is d2:
        return res

    for k2 in d2:
        if k2 not in d1:
            res[k2] = (default, d2[k2])

    return res