view mercurial/lsprofcalltree.py @ 13750:7eb82f88e157

# User Dan Villiom Podlaski Christiansen <danchr@gmail.com> # Date 1289564504 -3600 # Node ID b75264c15cc888cf38c3c7b8f619801e3c2589c7 # Parent 89b2e5d940f669e590096c6be70eee61c9172fff revsets: overload the branch() revset to also take a branch name. This should only change semantics in the specific case of a tag/branch conflict where the tag wasn't done on the branch with the same name. Previously, branch(whatever) would resolve to the branch of the tag in that case, whereas now it will resolve to the branch of the name. The previous behaviour, while documented, seemed very counter-intuitive to me. An alternate approach would be to introduce a new revset such as branchname() or namedbranch(). While this would retain backwards compatibility, the distinction between it and branch() would not be readily apparent to users. The most intuitive behaviour would be to have branch(x) require 'x' to be a branch name, and something like branchof(x) or samebranch(x) do what branch(x) currently does. Unfortunately, our backwards compatibility guarantees prevent us from doing that. Please note that while 'hg tag' guards against shadowing a branch, 'hg branch' does not. Besides, even if it did, that wouldn't solve the issue of conversions with such tags and branches...
author Matt Mackall <mpm@selenic.com>
date Wed, 23 Mar 2011 19:28:16 -0500
parents beae42f3d93b
children 071af8d385a9
line wrap: on
line source

"""
lsprofcalltree.py - lsprof output which is readable by kcachegrind

Authors:
    * David Allouche <david <at> allouche.net>
    * Jp Calderone & Itamar Shtull-Trauring
    * Johan Dahlin

This software may be used and distributed according to the terms
of the GNU General Public License, incorporated herein by reference.
"""

def label(code):
    if isinstance(code, str):
        return '~' + code    # built-in functions ('~' sorts at the end)
    else:
        return '%s %s:%d' % (code.co_name,
                             code.co_filename,
                             code.co_firstlineno)

class KCacheGrind(object):
    def __init__(self, profiler):
        self.data = profiler.getstats()
        self.out_file = None

    def output(self, out_file):
        self.out_file = out_file
        print >> out_file, 'events: Ticks'
        self._print_summary()
        for entry in self.data:
            self._entry(entry)

    def _print_summary(self):
        max_cost = 0
        for entry in self.data:
            totaltime = int(entry.totaltime * 1000)
            max_cost = max(max_cost, totaltime)
        print >> self.out_file, 'summary: %d' % (max_cost,)

    def _entry(self, entry):
        out_file = self.out_file

        code = entry.code
        #print >> out_file, 'ob=%s' % (code.co_filename,)
        if isinstance(code, str):
            print >> out_file, 'fi=~'
        else:
            print >> out_file, 'fi=%s' % (code.co_filename,)
        print >> out_file, 'fn=%s' % (label(code),)

        inlinetime = int(entry.inlinetime * 1000)
        if isinstance(code, str):
            print >> out_file, '0 ', inlinetime
        else:
            print >> out_file, '%d %d' % (code.co_firstlineno, inlinetime)

        # recursive calls are counted in entry.calls
        if entry.calls:
            calls = entry.calls
        else:
            calls = []

        if isinstance(code, str):
            lineno = 0
        else:
            lineno = code.co_firstlineno

        for subentry in calls:
            self._subentry(lineno, subentry)
        print >> out_file

    def _subentry(self, lineno, subentry):
        out_file = self.out_file
        code = subentry.code
        #print >> out_file, 'cob=%s' % (code.co_filename,)
        print >> out_file, 'cfn=%s' % (label(code),)
        if isinstance(code, str):
            print >> out_file, 'cfi=~'
            print >> out_file, 'calls=%d 0' % (subentry.callcount,)
        else:
            print >> out_file, 'cfi=%s' % (code.co_filename,)
            print >> out_file, 'calls=%d %d' % (
                subentry.callcount, code.co_firstlineno)

        totaltime = int(subentry.totaltime * 1000)
        print >> out_file, '%d %d' % (lineno, totaltime)