Mercurial > hg
view mercurial/pushkey.py @ 44739:828d3277618a stable
automation: always use latest Windows AMI
The old AMI isn't available any more.
We seem to run into this problem every few months. Amazon (or
Microsoft) appears to be removing the old AMIs when they are
superseded or something. Let's give up on tracking known images
and switch the image selection logic to use the latest published
image.
Differential Revision: https://phab.mercurial-scm.org/D8465
author | Gregory Szorc <gregory.szorc@gmail.com> |
---|---|
date | Sun, 19 Apr 2020 13:29:50 -0700 |
parents | 687b865b95ad |
children | d4ba4d51f85f |
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# pushkey.py - dispatching for pushing and pulling keys # # Copyright 2010 Matt Mackall <mpm@selenic.com> # # This software may be used and distributed according to the terms of the # GNU General Public License version 2 or any later version. from __future__ import absolute_import from . import ( bookmarks, encoding, obsolete, phases, ) def _nslist(repo): n = {} for k in _namespaces: n[k] = b"" if not obsolete.isenabled(repo, obsolete.exchangeopt): n.pop(b'obsolete') return n _namespaces = { b"namespaces": (lambda *x: False, _nslist), b"bookmarks": (bookmarks.pushbookmark, bookmarks.listbookmarks), b"phases": (phases.pushphase, phases.listphases), b"obsolete": (obsolete.pushmarker, obsolete.listmarkers), } def register(namespace, pushkey, listkeys): _namespaces[namespace] = (pushkey, listkeys) def _get(namespace): return _namespaces.get(namespace, (lambda *x: False, lambda *x: {})) def push(repo, namespace, key, old, new): '''should succeed iff value was old''' pk = _get(namespace)[0] return pk(repo, key, old, new) def list(repo, namespace): '''return a dict''' lk = _get(namespace)[1] return lk(repo) encode = encoding.fromlocal decode = encoding.tolocal def encodekeys(keys): """encode the content of a pushkey namespace for exchange over the wire""" return b'\n'.join([b'%s\t%s' % (encode(k), encode(v)) for k, v in keys]) def decodekeys(data): """decode the content of a pushkey namespace from exchange over the wire""" result = {} for l in data.splitlines(): k, v = l.split(b'\t') result[decode(k)] = decode(v) return result