view mercurial/dicthelpers.py @ 22285:85bded43cc80

largefiles: restore standins according to restored dirstate Before this patch, standins are restored from the NEW parent of the working directory at "hg rollback", and this causes: - standins removed in the rollback-ed revision are restored, and become orphan, because they are already marked as "R" in the restored dirstate and expected to be unlinked - standins added in the rollback-ed revision are left as they were before rollback, because they are not included in the new parent (this may not be so serious) This patch replaces the "merge.update" invocation with a specific implementation to restore standins according to restored dirstate. This is also the preparation to centralize the logic of updating largefiles into the function wrapping "merge.update" in the subsequent patch. After that patch, "merge.update" will also update largefiles in the working directory and be redundant for restoring standins only.
author FUJIWARA Katsunori <foozy@lares.dti.ne.jp>
date Sun, 24 Aug 2014 23:47:25 +0900
parents ed46c2b98b0d
children
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# dicthelpers.py - helper routines for Python dicts
#
# Copyright 2013 Facebook
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.

def diff(d1, d2, default=None):
    '''Return all key-value pairs that are different between d1 and d2.

    This includes keys that are present in one dict but not the other, and
    keys whose values are different. The return value is a dict with values
    being pairs of values from d1 and d2 respectively, and missing values
    treated as default, so if a value is missing from one dict and the same as
    default in the other, it will not be returned.'''
    res = {}
    if d1 is d2:
        # same dict, so diff is empty
        return res

    for k1, v1 in d1.iteritems():
        v2 = d2.get(k1, default)
        if v1 != v2:
            res[k1] = (v1, v2)

    for k2 in d2:
        if k2 not in d1:
            v2 = d2[k2]
            if v2 != default:
                res[k2] = (default, v2)

    return res

def join(d1, d2, default=None):
    '''Return all key-value pairs from both d1 and d2.

    This is akin to an outer join in relational algebra. The return value is a
    dict with values being pairs of values from d1 and d2 respectively, and
    missing values represented as default.'''
    res = {}

    for k1, v1 in d1.iteritems():
        if k1 in d2:
            res[k1] = (v1, d2[k1])
        else:
            res[k1] = (v1, default)

    if d1 is d2:
        return res

    for k2 in d2:
        if k2 not in d1:
            res[k2] = (default, d2[k2])

    return res