view mercurial/simplemerge.py @ 42743:8c9a6adec67a

rust-discovery: using the children cache in add_missing The DAG range computation often needs to get back to very old revisions, and turns out to be disproportionately long, given that the end goal is to remove the descendents of the given missing revisons from the undecided set. The fast iteration capabilities available in the Rust case make it possible to avoid the DAG range entirely, at the cost of precomputing the children cache, and to simply iterate on children of the given missing revisions. This is a case where staying on the same side of the interface between the two languages has clear benefits. On discoveries with initial undecided sets small enough to bypass sampling entirely, the total cost of computing the children cache and the subsequent iteration becomes better than the Python + C counterpart, which relies on reachableroots2. For example, on a repo with more than one million revisions with an initial undecided set of 11 elements, we get these figures: Rust version with simple iteration addcommons: 57.287us first undecided computation: 184.278334ms first children cache computation: 131.056us addmissings iteration: 42.766us first addinfo total: 185.24 ms Python + C version first addcommons: 0.29 ms addcommons 0.21 ms first undecided computation 191.35 ms addmissings 45.75 ms first addinfo total: 237.77 ms On discoveries with large undecided sets, the initial price paid makes the first addinfo slower than the Python + C version, but that's more than compensated by the gain in sampling and subsequent iterations. Here's an extreme example with an undecided set of a million revisions: Rust version: first undecided computation: 293.842629ms first children cache computation: 407.911297ms addmissings iteration: 34.312869ms first addinfo total: 776.02 ms taking initial sample query 2: sampling time: 1318.38 ms query 2; still undecided: 1005013, sample size is: 200 addmissings: 143.062us Python + C version: first undecided computation 298.13 ms addmissings 80.13 ms first addinfo total: 399.62 ms taking initial sample query 2: sampling time: 3957.23 ms query 2; still undecided: 1005013, sample size is: 200 addmissings 52.88 ms Differential Revision: https://phab.mercurial-scm.org/D6428
author Georges Racinet <georges.racinet@octobus.net>
date Tue, 16 Apr 2019 01:16:39 +0200
parents aaad36b88298
children 2372284d9457
line wrap: on
line source

# Copyright (C) 2004, 2005 Canonical Ltd
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, see <http://www.gnu.org/licenses/>.

# mbp: "you know that thing where cvs gives you conflict markers?"
# s: "i hate that."

from __future__ import absolute_import

from .i18n import _
from . import (
    error,
    mdiff,
    pycompat,
)
from .utils import (
    stringutil,
)

class CantReprocessAndShowBase(Exception):
    pass

def intersect(ra, rb):
    """Given two ranges return the range where they intersect or None.

    >>> intersect((0, 10), (0, 6))
    (0, 6)
    >>> intersect((0, 10), (5, 15))
    (5, 10)
    >>> intersect((0, 10), (10, 15))
    >>> intersect((0, 9), (10, 15))
    >>> intersect((0, 9), (7, 15))
    (7, 9)
    """
    assert ra[0] <= ra[1]
    assert rb[0] <= rb[1]

    sa = max(ra[0], rb[0])
    sb = min(ra[1], rb[1])
    if sa < sb:
        return sa, sb
    else:
        return None

def compare_range(a, astart, aend, b, bstart, bend):
    """Compare a[astart:aend] == b[bstart:bend], without slicing.
    """
    if (aend - astart) != (bend - bstart):
        return False
    for ia, ib in zip(pycompat.xrange(astart, aend),
                      pycompat.xrange(bstart, bend)):
        if a[ia] != b[ib]:
            return False
    else:
        return True

class Merge3Text(object):
    """3-way merge of texts.

    Given strings BASE, OTHER, THIS, tries to produce a combined text
    incorporating the changes from both BASE->OTHER and BASE->THIS."""
    def __init__(self, basetext, atext, btext, base=None, a=None, b=None):
        self.basetext = basetext
        self.atext = atext
        self.btext = btext
        if base is None:
            base = mdiff.splitnewlines(basetext)
        if a is None:
            a = mdiff.splitnewlines(atext)
        if b is None:
            b = mdiff.splitnewlines(btext)
        self.base = base
        self.a = a
        self.b = b

    def merge_lines(self,
                    name_a=None,
                    name_b=None,
                    name_base=None,
                    start_marker='<<<<<<<',
                    mid_marker='=======',
                    end_marker='>>>>>>>',
                    base_marker=None,
                    localorother=None,
                    minimize=False):
        """Return merge in cvs-like form.
        """
        self.conflicts = False
        newline = '\n'
        if len(self.a) > 0:
            if self.a[0].endswith('\r\n'):
                newline = '\r\n'
            elif self.a[0].endswith('\r'):
                newline = '\r'
        if name_a and start_marker:
            start_marker = start_marker + ' ' + name_a
        if name_b and end_marker:
            end_marker = end_marker + ' ' + name_b
        if name_base and base_marker:
            base_marker = base_marker + ' ' + name_base
        merge_regions = self.merge_regions()
        if minimize:
            merge_regions = self.minimize(merge_regions)
        for t in merge_regions:
            what = t[0]
            if what == 'unchanged':
                for i in range(t[1], t[2]):
                    yield self.base[i]
            elif what == 'a' or what == 'same':
                for i in range(t[1], t[2]):
                    yield self.a[i]
            elif what == 'b':
                for i in range(t[1], t[2]):
                    yield self.b[i]
            elif what == 'conflict':
                if localorother == 'local':
                    for i in range(t[3], t[4]):
                        yield self.a[i]
                elif localorother == 'other':
                    for i in range(t[5], t[6]):
                        yield self.b[i]
                else:
                    self.conflicts = True
                    if start_marker is not None:
                        yield start_marker + newline
                    for i in range(t[3], t[4]):
                        yield self.a[i]
                    if base_marker is not None:
                        yield base_marker + newline
                        for i in range(t[1], t[2]):
                            yield self.base[i]
                    if mid_marker is not None:
                        yield mid_marker + newline
                    for i in range(t[5], t[6]):
                        yield self.b[i]
                    if end_marker is not None:
                        yield end_marker + newline
            else:
                raise ValueError(what)

    def merge_groups(self):
        """Yield sequence of line groups.  Each one is a tuple:

        'unchanged', lines
             Lines unchanged from base

        'a', lines
             Lines taken from a

        'same', lines
             Lines taken from a (and equal to b)

        'b', lines
             Lines taken from b

        'conflict', base_lines, a_lines, b_lines
             Lines from base were changed to either a or b and conflict.
        """
        for t in self.merge_regions():
            what = t[0]
            if what == 'unchanged':
                yield what, self.base[t[1]:t[2]]
            elif what == 'a' or what == 'same':
                yield what, self.a[t[1]:t[2]]
            elif what == 'b':
                yield what, self.b[t[1]:t[2]]
            elif what == 'conflict':
                yield (what,
                       self.base[t[1]:t[2]],
                       self.a[t[3]:t[4]],
                       self.b[t[5]:t[6]])
            else:
                raise ValueError(what)

    def merge_regions(self):
        """Return sequences of matching and conflicting regions.

        This returns tuples, where the first value says what kind we
        have:

        'unchanged', start, end
             Take a region of base[start:end]

        'same', astart, aend
             b and a are different from base but give the same result

        'a', start, end
             Non-clashing insertion from a[start:end]

        'conflict', zstart, zend, astart, aend, bstart, bend
            Conflict between a and b, with z as common ancestor

        Method is as follows:

        The two sequences align only on regions which match the base
        and both descendants.  These are found by doing a two-way diff
        of each one against the base, and then finding the
        intersections between those regions.  These "sync regions"
        are by definition unchanged in both and easily dealt with.

        The regions in between can be in any of three cases:
        conflicted, or changed on only one side.
        """

        # section a[0:ia] has been disposed of, etc
        iz = ia = ib = 0

        for region in self.find_sync_regions():
            zmatch, zend, amatch, aend, bmatch, bend = region
            #print 'match base [%d:%d]' % (zmatch, zend)

            matchlen = zend - zmatch
            assert matchlen >= 0
            assert matchlen == (aend - amatch)
            assert matchlen == (bend - bmatch)

            len_a = amatch - ia
            len_b = bmatch - ib
            len_base = zmatch - iz
            assert len_a >= 0
            assert len_b >= 0
            assert len_base >= 0

            #print 'unmatched a=%d, b=%d' % (len_a, len_b)

            if len_a or len_b:
                # try to avoid actually slicing the lists
                equal_a = compare_range(self.a, ia, amatch,
                                        self.base, iz, zmatch)
                equal_b = compare_range(self.b, ib, bmatch,
                                        self.base, iz, zmatch)
                same = compare_range(self.a, ia, amatch,
                                     self.b, ib, bmatch)

                if same:
                    yield 'same', ia, amatch
                elif equal_a and not equal_b:
                    yield 'b', ib, bmatch
                elif equal_b and not equal_a:
                    yield 'a', ia, amatch
                elif not equal_a and not equal_b:
                    yield 'conflict', iz, zmatch, ia, amatch, ib, bmatch
                else:
                    raise AssertionError("can't handle a=b=base but unmatched")

                ia = amatch
                ib = bmatch
            iz = zmatch

            # if the same part of the base was deleted on both sides
            # that's OK, we can just skip it.


            if matchlen > 0:
                assert ia == amatch
                assert ib == bmatch
                assert iz == zmatch

                yield 'unchanged', zmatch, zend
                iz = zend
                ia = aend
                ib = bend

    def minimize(self, merge_regions):
        """Trim conflict regions of lines where A and B sides match.

        Lines where both A and B have made the same changes at the beginning
        or the end of each merge region are eliminated from the conflict
        region and are instead considered the same.
        """
        for region in merge_regions:
            if region[0] != "conflict":
                yield region
                continue
            issue, z1, z2, a1, a2, b1, b2 = region
            alen = a2 - a1
            blen = b2 - b1

            # find matches at the front
            ii = 0
            while (ii < alen and ii < blen and
                   self.a[a1 + ii] == self.b[b1 + ii]):
                ii += 1
            startmatches = ii

            # find matches at the end
            ii = 0
            while (ii < alen and ii < blen and
                   self.a[a2 - ii - 1] == self.b[b2 - ii - 1]):
                ii += 1
            endmatches = ii

            if startmatches > 0:
                yield 'same', a1, a1 + startmatches

            yield ('conflict', z1, z2,
                    a1 + startmatches, a2 - endmatches,
                    b1 + startmatches, b2 - endmatches)

            if endmatches > 0:
                yield 'same', a2 - endmatches, a2

    def find_sync_regions(self):
        """Return a list of sync regions, where both descendants match the base.

        Generates a list of (base1, base2, a1, a2, b1, b2).  There is
        always a zero-length sync region at the end of all the files.
        """

        ia = ib = 0
        amatches = mdiff.get_matching_blocks(self.basetext, self.atext)
        bmatches = mdiff.get_matching_blocks(self.basetext, self.btext)
        len_a = len(amatches)
        len_b = len(bmatches)

        sl = []

        while ia < len_a and ib < len_b:
            abase, amatch, alen = amatches[ia]
            bbase, bmatch, blen = bmatches[ib]

            # there is an unconflicted block at i; how long does it
            # extend?  until whichever one ends earlier.
            i = intersect((abase, abase + alen), (bbase, bbase + blen))
            if i:
                intbase = i[0]
                intend = i[1]
                intlen = intend - intbase

                # found a match of base[i[0], i[1]]; this may be less than
                # the region that matches in either one
                assert intlen <= alen
                assert intlen <= blen
                assert abase <= intbase
                assert bbase <= intbase

                asub = amatch + (intbase - abase)
                bsub = bmatch + (intbase - bbase)
                aend = asub + intlen
                bend = bsub + intlen

                assert self.base[intbase:intend] == self.a[asub:aend], (
                        (self.base[intbase:intend], self.a[asub:aend]))

                assert self.base[intbase:intend] == self.b[bsub:bend]

                sl.append((intbase, intend,
                           asub, aend,
                           bsub, bend))

            # advance whichever one ends first in the base text
            if (abase + alen) < (bbase + blen):
                ia += 1
            else:
                ib += 1

        intbase = len(self.base)
        abase = len(self.a)
        bbase = len(self.b)
        sl.append((intbase, intbase, abase, abase, bbase, bbase))

        return sl

    def find_unconflicted(self):
        """Return a list of ranges in base that are not conflicted."""
        am = mdiff.get_matching_blocks(self.basetext, self.atext)
        bm = mdiff.get_matching_blocks(self.basetext, self.btext)

        unc = []

        while am and bm:
            # there is an unconflicted block at i; how long does it
            # extend?  until whichever one ends earlier.
            a1 = am[0][0]
            a2 = a1 + am[0][2]
            b1 = bm[0][0]
            b2 = b1 + bm[0][2]
            i = intersect((a1, a2), (b1, b2))
            if i:
                unc.append(i)

            if a2 < b2:
                del am[0]
            else:
                del bm[0]

        return unc

def _verifytext(text, path, ui, opts):
    """verifies that text is non-binary (unless opts[text] is passed,
    then we just warn)"""
    if stringutil.binary(text):
        msg = _("%s looks like a binary file.") % path
        if not opts.get('quiet'):
            ui.warn(_('warning: %s\n') % msg)
        if not opts.get('text'):
            raise error.Abort(msg)
    return text

def _picklabels(defaults, overrides):
    if len(overrides) > 3:
        raise error.Abort(_("can only specify three labels."))
    result = defaults[:]
    for i, override in enumerate(overrides):
        result[i] = override
    return result

def simplemerge(ui, localctx, basectx, otherctx, **opts):
    """Performs the simplemerge algorithm.

    The merged result is written into `localctx`.
    """
    opts = pycompat.byteskwargs(opts)

    def readctx(ctx):
        # Merges were always run in the working copy before, which means
        # they used decoded data, if the user defined any repository
        # filters.
        #
        # Maintain that behavior today for BC, though perhaps in the future
        # it'd be worth considering whether merging encoded data (what the
        # repository usually sees) might be more useful.
        return _verifytext(ctx.decodeddata(), ctx.path(), ui, opts)

    mode = opts.get('mode','merge')
    name_a, name_b, name_base = None, None, None
    if mode != 'union':
        name_a, name_b, name_base = _picklabels([localctx.path(),
                                                 otherctx.path(), None],
                                                opts.get('label', []))

    try:
        localtext = readctx(localctx)
        basetext = readctx(basectx)
        othertext = readctx(otherctx)
    except error.Abort:
        return 1

    m3 = Merge3Text(basetext, localtext, othertext)
    extrakwargs = {
            "localorother": opts.get("localorother", None),
            'minimize': True,
        }
    if mode == 'union':
        extrakwargs['start_marker'] = None
        extrakwargs['mid_marker'] = None
        extrakwargs['end_marker'] = None
    elif name_base is not None:
        extrakwargs['base_marker'] = '|||||||'
        extrakwargs['name_base'] = name_base
        extrakwargs['minimize'] = False

    mergedtext = ""
    for line in m3.merge_lines(name_a=name_a, name_b=name_b,
                               **pycompat.strkwargs(extrakwargs)):
        if opts.get('print'):
            ui.fout.write(line)
        else:
            mergedtext += line

    if not opts.get('print'):
        localctx.write(mergedtext, localctx.flags())

    if m3.conflicts and not mode == 'union':
        return 1