Mercurial > hg
view mercurial/ancestor.py @ 10239:8e4be44a676f
Find right hg command for detached process
On Windows, Mercurial can be run from the python script of from a frozen
executable. In the first case, we have to call the python interpreter since the
script is not executable. Frozen executable can be called directly.
Fix 3/3 for issue421
author | Patrick Mezard <pmezard@gmail.com> |
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date | Wed, 06 Jan 2010 21:11:58 +0100 |
parents | 806e6b6cb8d8 |
children | d6512b3e9ac0 |
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# ancestor.py - generic DAG ancestor algorithm for mercurial # # Copyright 2006 Matt Mackall <mpm@selenic.com> # # This software may be used and distributed according to the terms of the # GNU General Public License version 2, incorporated herein by reference. import heapq def ancestor(a, b, pfunc): """ return a minimal-distance ancestor of nodes a and b, or None if there is no such ancestor. Note that there can be several ancestors with the same (minimal) distance, and the one returned is arbitrary. pfunc must return a list of parent vertices for a given vertex """ if a == b: return a # find depth from root of all ancestors parentcache = {} visit = [a, b] depth = {} while visit: vertex = visit[-1] pl = pfunc(vertex) parentcache[vertex] = pl if not pl: depth[vertex] = 0 visit.pop() else: for p in pl: if p == a or p == b: # did we find a or b as a parent? return p # we're done if p not in depth: visit.append(p) if visit[-1] == vertex: depth[vertex] = min([depth[p] for p in pl]) - 1 visit.pop() # traverse ancestors in order of decreasing distance from root def ancestors(vertex): h = [(depth[vertex], vertex)] seen = set() while h: d, n = heapq.heappop(h) if n not in seen: seen.add(n) yield (d, n) for p in parentcache[n]: heapq.heappush(h, (depth[p], p)) def generations(vertex): sg, s = None, set() for g, v in ancestors(vertex): if g != sg: if sg: yield sg, s sg, s = g, set((v,)) else: s.add(v) yield sg, s x = generations(a) y = generations(b) gx = x.next() gy = y.next() # increment each ancestor list until it is closer to root than # the other, or they match try: while 1: if gx[0] == gy[0]: for v in gx[1]: if v in gy[1]: return v gy = y.next() gx = x.next() elif gx[0] > gy[0]: gy = y.next() else: gx = x.next() except StopIteration: return None