py3: decode username and password before SMTP login
smtplib.SMTP.login() requires str on Python 3.
For 'password', we only need to decode when value comes from config as
getpass() returns the correct type already.
# pushkey.py - dispatching for pushing and pulling keys
#
# Copyright 2010 Matt Mackall <mpm@selenic.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
from __future__ import absolute_import
from . import (
bookmarks,
encoding,
obsolete,
phases,
)
def _nslist(repo):
n = {}
for k in _namespaces:
n[k] = b""
if not obsolete.isenabled(repo, obsolete.exchangeopt):
n.pop(b'obsolete')
return n
_namespaces = {
b"namespaces": (lambda *x: False, _nslist),
b"bookmarks": (bookmarks.pushbookmark, bookmarks.listbookmarks),
b"phases": (phases.pushphase, phases.listphases),
b"obsolete": (obsolete.pushmarker, obsolete.listmarkers),
}
def register(namespace, pushkey, listkeys):
_namespaces[namespace] = (pushkey, listkeys)
def _get(namespace):
return _namespaces.get(namespace, (lambda *x: False, lambda *x: {}))
def push(repo, namespace, key, old, new):
'''should succeed iff value was old'''
pk = _get(namespace)[0]
return pk(repo, key, old, new)
def list(repo, namespace):
'''return a dict'''
lk = _get(namespace)[1]
return lk(repo)
encode = encoding.fromlocal
decode = encoding.tolocal
def encodekeys(keys):
"""encode the content of a pushkey namespace for exchange over the wire"""
return b'\n'.join([b'%s\t%s' % (encode(k), encode(v)) for k, v in keys])
def decodekeys(data):
"""decode the content of a pushkey namespace from exchange over the wire"""
result = {}
for l in data.splitlines():
k, v = l.split(b'\t')
result[decode(k)] = decode(v)
return result