py3: add PY23() macro to switch string literal depending on python version
I have no better idea to work around the bytes-unicode divergence of
Py_BuildValue(). Maybe we can write a code transformer for C extensions? :)
/*
util.h - utility functions for interfacing with the various python APIs.
This software may be used and distributed according to the terms of
the GNU General Public License, incorporated herein by reference.
*/
#ifndef _HG_UTIL_H_
#define _HG_UTIL_H_
#include "compat.h"
#if PY_MAJOR_VERSION >= 3
#define IS_PY3K
#endif
/* helper to switch things like string literal depending on Python version */
#ifdef IS_PY3K
#define PY23(py2, py3) py3
#else
#define PY23(py2, py3) py2
#endif
/* clang-format off */
typedef struct {
PyObject_HEAD
char state;
int mode;
int size;
int mtime;
} dirstateTupleObject;
/* clang-format on */
extern PyTypeObject dirstateTupleType;
#define dirstate_tuple_check(op) (Py_TYPE(op) == &dirstateTupleType)
#ifndef MIN
#define MIN(a, b) (((a) < (b)) ? (a) : (b))
#endif
/* VC9 doesn't include bool and lacks stdbool.h based on my searching */
#if defined(_MSC_VER) || __STDC_VERSION__ < 199901L
#define true 1
#define false 0
typedef unsigned char bool;
#else
#include <stdbool.h>
#endif
static inline PyObject *_dict_new_presized(Py_ssize_t expected_size)
{
/* _PyDict_NewPresized expects a minused parameter, but it actually
creates a dictionary that's the nearest power of two bigger than the
parameter. For example, with the initial minused = 1000, the
dictionary created has size 1024. Of course in a lot of cases that
can be greater than the maximum load factor Python's dict object
expects (= 2/3), so as soon as we cross the threshold we'll resize
anyway. So create a dictionary that's at least 3/2 the size. */
return _PyDict_NewPresized(((1 + expected_size) / 2) * 3);
}
#endif /* _HG_UTIL_H_ */