templatefuncs: do not stringify result of if*() expression
Returning a generator means that the result is a byte string. I can't find
any reason to make the "if" condition lazy since it is evaluated anyway
when {if()} has to be evaluated. So let's simply make if*() return an input
expression unmodified.
# memory.py - track memory usage
#
# Copyright 2009 Matt Mackall <mpm@selenic.com> and others
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
'''helper extension to measure memory usage
Reads current and peak memory usage from ``/proc/self/status`` and
prints it to ``stderr`` on exit.
'''
from __future__ import absolute_import
def memusage(ui):
"""Report memory usage of the current process."""
result = {'peak': 0, 'rss': 0}
with open('/proc/self/status', 'r') as status:
# This will only work on systems with a /proc file system
# (like Linux).
for line in status:
parts = line.split()
key = parts[0][2:-1].lower()
if key in result:
result[key] = int(parts[1])
ui.write_err(", ".join(["%s: %.1f MiB" % (k, v / 1024.0)
for k, v in result.iteritems()]) + "\n")
def extsetup(ui):
ui.atexit(memusage, ui)