stream-clone: check is a compatible protocol can be found
The previous code was explicitly checking if "v2" is listed in the "stream"
bundle2 capability. The new code is checking is there is anything common
between the versions supported client side and server side overlaps.
This prepare the introduction of more stream version than "v2".
# Randomized torture test generation for bdiff
import random
import sys
from mercurial import (
mdiff,
pycompat,
)
def reducetest(a, b):
tries = 0
reductions = 0
print("reducing...")
while tries < 1000:
a2 = (
"\n".join(l for l in a.splitlines() if random.randint(0, 100) > 0)
+ "\n"
)
b2 = (
"\n".join(l for l in b.splitlines() if random.randint(0, 100) > 0)
+ "\n"
)
if a2 == a and b2 == b:
continue
if a2 == b2:
continue
tries += 1
try:
test1(a, b)
except Exception:
reductions += 1
tries = 0
a = a2
b = b2
print("reduced:", reductions, len(a) + len(b), repr(a), repr(b))
try:
test1(a, b)
except Exception as inst:
print("failed:", inst)
sys.exit(0)
def test1(a, b):
d = mdiff.textdiff(a, b)
if not d:
raise ValueError("empty")
c = mdiff.patches(a, [d])
if c != b:
raise ValueError("bad")
def testwrap(a, b):
try:
test1(a, b)
return
except Exception as inst:
print("exception:", inst)
reducetest(a, b)
def test(a, b):
testwrap(a, b)
testwrap(b, a)
def rndtest(size, noise):
a = []
src = " aaaaaaaabbbbccd"
for x in pycompat.xrange(size):
a.append(src[random.randint(0, len(src) - 1)])
while True:
b = [c for c in a if random.randint(0, 99) > noise]
b2 = []
for c in b:
b2.append(c)
while random.randint(0, 99) < noise:
b2.append(src[random.randint(0, len(src) - 1)])
if b2 != a:
break
a = "\n".join(a) + "\n"
b = "\n".join(b2) + "\n"
test(a, b)
maxvol = 10000
startsize = 2
while True:
size = startsize
count = 0
while size < maxvol:
print(size)
volume = 0
while volume < maxvol:
rndtest(size, 2)
volume += size
count += 2
size *= 2
maxvol *= 4
startsize *= 4