stream-clone-test: simplify the test for getbundle with stream=1
The core of this tests is about checking we receive a stream bundle with such
request. We don't need to look at too much of the details of the stream itself.
Since the content of the stream if shifting overtime, Such check is very
fragile and consume a lot of time for little value when adjusting formats,
caches, and protocol.
So we reduce the size of what we check to focus on "is this a stream clone"
question.
This test file aims at test topological iteration and the various configuration it can has.
$ cat >> $HGRCPATH << EOF
> [command-templates]
> log={rev}\n
> EOF
On this simple example, all topological branch are displayed in turn until we
can finally display 0. this implies skipping from 8 to 3 and coming back to 7
later.
$ hg init test01
$ cd test01
$ hg unbundle $TESTDIR/bundles/remote.hg
adding changesets
adding manifests
adding file changes
added 9 changesets with 7 changes to 4 files (+1 heads)
new changesets bfaf4b5cbf01:916f1afdef90 (9 drafts)
(run 'hg heads' to see heads, 'hg merge' to merge)
$ hg log -G
o 8
|
| o 7
| |
| o 6
| |
| o 5
| |
| o 4
| |
o | 3
| |
o | 2
| |
o | 1
|/
o 0
(display all nodes)
$ hg log -G -r 'sort(all(), topo)'
o 8
|
o 3
|
o 2
|
o 1
|
| o 7
| |
| o 6
| |
| o 5
| |
| o 4
|/
o 0
(display nodes filtered by log options)
$ hg log -G -r 'sort(all(), topo)' -k '.3'
o 8
|
o 3
|
~
o 7
|
o 6
|
~
(revset skipping nodes)
$ hg log -G --rev 'sort(not (2+6), topo)'
o 8
|
o 3
:
o 1
|
| o 7
| :
| o 5
| |
| o 4
|/
o 0
(begin) from the other branch
$ hg log -G -r 'sort(all(), topo, topo.firstbranch=5)'
o 7
|
o 6
|
o 5
|
o 4
|
| o 8
| |
| o 3
| |
| o 2
| |
| o 1
|/
o 0
Topological sort can be turned on via config
$ cat >> $HGRCPATH << EOF
> [experimental]
> log.topo=true
> EOF
$ hg log -G
o 8
|
o 3
|
o 2
|
o 1
|
| o 7
| |
| o 6
| |
| o 5
| |
| o 4
|/
o 0
Does not affect non-graph log
$ hg log -T '{rev}\n'
8
7
6
5
4
3
2
1
0