Mercurial > hg
view tests/test-lrucachedict.py @ 35565:bdae51a83dfb
clonebundle: make it possible to retrieve the initial bundle through largefile
By setting the default path early enough, we make it possible to retrieve a
clone bundle as a largefile from the repository we are cloning.
But... why?
Clone bundle is a great feature to speeds up clone of large repository. However
one of the main obstacle for clone bundle deployment is the authentication
scheme. For non public project, just putting a static file on some random CDN is
not an option as we have to make sure people have the proper permission to
retrieves the bundle. On the other hand, 'largefiles' already have all the
necessary logic to serve arbitrary binary files -after- an authentication
checks. So reusing an existing large file infrastructure can be a significant
shortcut to clone bundle in this kind of closed environment.
The idea might seems strange, but the necessary update to the large file
extensions are quite small while the benefits are huge. In addition, since all
the extra logic live in the 'largefiles' extensions, core does not have to know
anything about it.
author | Boris Feld <boris.feld@octobus.net> |
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date | Thu, 21 Dec 2017 13:58:11 +0100 |
parents | 79add5a4e857 |
children | 067f7d2c7d60 |
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from __future__ import absolute_import, print_function from mercurial import ( util, ) def printifpresent(d, xs, name='d'): for x in xs: present = x in d print("'%s' in %s: %s" % (x, name, present)) if present: print("%s['%s']: %s" % (name, x, d[x])) def test_lrucachedict(): d = util.lrucachedict(4) d['a'] = 'va' d['b'] = 'vb' d['c'] = 'vc' d['d'] = 'vd' # all of these should be present printifpresent(d, ['a', 'b', 'c', 'd']) # 'a' should be dropped because it was least recently used d['e'] = 've' printifpresent(d, ['a', 'b', 'c', 'd', 'e']) assert d.get('a') is None assert d.get('e') == 've' # touch entries in some order (get or set). d['e'] d['c'] = 'vc2' d['d'] d['b'] = 'vb2' # 'e' should be dropped now d['f'] = 'vf' printifpresent(d, ['b', 'c', 'd', 'e', 'f']) d.clear() printifpresent(d, ['b', 'c', 'd', 'e', 'f']) # Now test dicts that aren't full. d = util.lrucachedict(4) d['a'] = 1 d['b'] = 2 d['a'] d['b'] printifpresent(d, ['a', 'b']) # test copy method d = util.lrucachedict(4) d['a'] = 'va3' d['b'] = 'vb3' d['c'] = 'vc3' d['d'] = 'vd3' dc = d.copy() # all of these should be present print("\nAll of these should be present:") printifpresent(dc, ['a', 'b', 'c', 'd'], 'dc') # 'a' should be dropped because it was least recently used print("\nAll of these except 'a' should be present:") dc['e'] = 've3' printifpresent(dc, ['a', 'b', 'c', 'd', 'e'], 'dc') # contents and order of original dict should remain unchanged print("\nThese should be in reverse alphabetical order and read 'v?3':") dc['b'] = 'vb3_new' for k in list(iter(d)): print("d['%s']: %s" % (k, d[k])) if __name__ == '__main__': test_lrucachedict()