view tests/test-lrucachedict.py @ 23301:c10dc5568069

context.status: wipe deleted/unknown/ignored fields when reversed It makes no sense to request reverse status (i.e. changes from the working copy to its parent) and then look at the deleted, unknown or ignored fields. If you do, you would get the result from the forward status (changes from parent to the working copy). Instead of giving a nonsensical answer to a nonsensical question, it seems a little saner to return empty lists. It might be best if we could prevent the caller accessing these lists, but it's doubtful it's worth the trouble.
author Martin von Zweigbergk <martinvonz@google.com>
date Wed, 12 Nov 2014 21:19:07 -0800
parents 887ffa22fd0d
children 45d996a566d7
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from mercurial import util

def printifpresent(d, xs):
    for x in xs:
        present = x in d
        print "'%s' in d: %s" % (x, present)
        if present:
            print "d['%s']: %s" % (x, d[x])

def test_lrucachedict():
    d = util.lrucachedict(4)
    d['a'] = 'va'
    d['b'] = 'vb'
    d['c'] = 'vc'
    d['d'] = 'vd'

    # all of these should be present
    printifpresent(d, ['a', 'b', 'c', 'd'])

    # 'a' should be dropped because it was least recently used
    d['e'] = 've'
    printifpresent(d, ['a', 'b', 'c', 'd', 'e'])

    # touch entries in some order (get or set).
    d['e']
    d['c'] = 'vc2'
    d['d']
    d['b'] = 'vb2'

    # 'e' should be dropped now
    d['f'] = 'vf'
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

    d.clear()
    printifpresent(d, ['b', 'c', 'd', 'e', 'f'])

if __name__ == '__main__':
    test_lrucachedict()