bookmark: complexity pull-push test to have deeper tree
This changeset only touch test.
The previous test was correct, it tested that the successors of an old bookmark
position was seen as a valid destination for bookmark.
However, a newer version is made for two reason:
(1) The new test check further. It check that the descendant of the successors
is a valid destination
(2) An ever more complexe test is needed to validate a future fix to issue 3680
Splitting complexification of the test and actual bugfix help to reduce the
noise in the bugfix changeset. Issue 3680 is NOT fixed by this changeset.
#!/usr/bin/env python
"""This does HTTP GET requests given a host:port and path and returns
a subset of the headers plus the body of the result."""
import httplib, sys
try:
import msvcrt, os
msvcrt.setmode(sys.stdout.fileno(), os.O_BINARY)
msvcrt.setmode(sys.stderr.fileno(), os.O_BINARY)
except ImportError:
pass
twice = False
if '--twice' in sys.argv:
sys.argv.remove('--twice')
twice = True
reasons = {'Not modified': 'Not Modified'} # python 2.4
tag = None
def request(host, path, show):
assert not path.startswith('/'), path
global tag
headers = {}
if tag:
headers['If-None-Match'] = tag
conn = httplib.HTTPConnection(host)
conn.request("GET", '/' + path, None, headers)
response = conn.getresponse()
print response.status, reasons.get(response.reason, response.reason)
for h in [h.lower() for h in show]:
if response.getheader(h, None) is not None:
print "%s: %s" % (h, response.getheader(h))
print
data = response.read()
sys.stdout.write(data)
if twice and response.getheader('ETag', None):
tag = response.getheader('ETag')
return response.status
status = request(sys.argv[1], sys.argv[2], sys.argv[3:])
if twice:
status = request(sys.argv[1], sys.argv[2], sys.argv[3:])
if 200 <= status <= 305:
sys.exit(0)
sys.exit(1)