view mercurial/strutil.py @ 15976:d1c74c6151c9 stable

copies: eliminate criss-crosses when chaining Before the copies refactoring, we declared that if a and b were present in source and destination, we ignored copies between them. The refactored code could however report b was a copy of a and vice versa in a situation where we looked for differences between two identical changesets that copy a to b. y / x \ y'
author Matt Mackall <mpm@selenic.com>
date Tue, 24 Jan 2012 17:16:29 -0600
parents 25e572394f5c
children b723f05ec49b
line wrap: on
line source

# strutil.py - string utilities for Mercurial
#
# Copyright 2006 Vadim Gelfer <vadim.gelfer@gmail.com>
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.

def findall(haystack, needle, start=0, end=None):
    if end is None:
        end = len(haystack)
    if end < 0:
        end += len(haystack)
    if start < 0:
        start += len(haystack)
    while start < end:
        c = haystack.find(needle, start, end)
        if c == -1:
            break
        yield c
        start = c + 1

def rfindall(haystack, needle, start=0, end=None):
    if end is None:
        end = len(haystack)
    if end < 0:
        end += len(haystack)
    if start < 0:
        start += len(haystack)
    while end >= 0:
        c = haystack.rfind(needle, start, end)
        if c == -1:
            break
        yield c
        end = c - 1