view mercurial/dicthelpers.py @ 22013:de5cee8ba088

cmdutil: use '[committemplate]' section like as map file for style definition Before this patch, each template definitions for 'changeset*' in '[committemplate]' section have to be written fully from scratch, even though many parts of them may be common. This patch uses '[committemplate]' section like as the map file for the style definition. All items other than 'changeset' can be referred from others. This can reduce total cost of template customization in '[committemplate]' section. When the commit template other than '[committemplate] changeset' is chosen by 'editform', putting '[committemplate] changeset' value into the cache of the templater causes unexpected result, because the templater stores the specified (= chosen) template definition into own cache as 'changeset' at construction time. This is the reason why '[committemplate] changeset' can't be referred from others.
author FUJIWARA Katsunori <foozy@lares.dti.ne.jp>
date Sat, 02 Aug 2014 21:46:27 +0900
parents ed46c2b98b0d
children
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# dicthelpers.py - helper routines for Python dicts
#
# Copyright 2013 Facebook
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.

def diff(d1, d2, default=None):
    '''Return all key-value pairs that are different between d1 and d2.

    This includes keys that are present in one dict but not the other, and
    keys whose values are different. The return value is a dict with values
    being pairs of values from d1 and d2 respectively, and missing values
    treated as default, so if a value is missing from one dict and the same as
    default in the other, it will not be returned.'''
    res = {}
    if d1 is d2:
        # same dict, so diff is empty
        return res

    for k1, v1 in d1.iteritems():
        v2 = d2.get(k1, default)
        if v1 != v2:
            res[k1] = (v1, v2)

    for k2 in d2:
        if k2 not in d1:
            v2 = d2[k2]
            if v2 != default:
                res[k2] = (default, v2)

    return res

def join(d1, d2, default=None):
    '''Return all key-value pairs from both d1 and d2.

    This is akin to an outer join in relational algebra. The return value is a
    dict with values being pairs of values from d1 and d2 respectively, and
    missing values represented as default.'''
    res = {}

    for k1, v1 in d1.iteritems():
        if k1 in d2:
            res[k1] = (v1, d2[k1])
        else:
            res[k1] = (v1, default)

    if d1 is d2:
        return res

    for k2 in d2:
        if k2 not in d1:
            res[k2] = (default, d2[k2])

    return res