Permission handling for the other OS
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Permission handling for the other OS
From: K Thananchayan <thananck@yahoo.com>
Preserve exec permission under Windows on existing source files. Not an ideal
solution as there is no way to specify exec permission for a new file.
Nevertheless, this helps working on crossplatform projects.
manifest hash:
c50da52ad4645f40bd6204c4fd458e880bc3f801
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# util.py - utility functions and platform specfic implementations
#
# Copyright 2005 K. Thananchayan <thananck@yahoo.com>
#
# This software may be used and distributed according to the terms
# of the GNU General Public License, incorporated herein by reference.
import os
def rename(src, dst):
try:
os.rename(src, dst)
except:
os.unlink(dst)
os.rename(src, dst)
# Platfor specific varients
if os.name == 'nt':
def is_exec(f, last):
return last
def set_exec(f, mode):
pass
def pconvert(path):
return path.replace("\\", "/")
def makelock(info, pathname):
ld = os.open(pathname, os.O_CREAT | os.O_WRONLY | os.O_EXCL)
os.write(ld, info)
os.close(ld)
def readlock(pathname):
return file(pathname).read()
else:
def is_exec(f, last):
return (os.stat(f).st_mode & 0100 != 0)
def set_exec(f, mode):
s = os.stat(f).st_mode
if (s & 0100 != 0) == mode:
return
if mode:
# Turn on +x for every +r bit when making a file executable
# and obey umask.
umask = os.umask(0)
os.umask(umask)
os.chmod(f, s | (s & 0444) >> 2 & ~umask)
else:
os.chmod(f, s & 0666)
def pconvert(path):
return path
def makelock(info, pathname):
os.symlink(info, pathname)
def readlock(pathname):
return os.readlink(pathname)