Mercurial > hg
view mercurial/ancestor.py @ 10579:f142fa3c0a8c stable
Make annotate --follow an alias for -f/--file to behave like in older versions
Since 98a0421b9e52 annotate follows copies/renames by default, but the output
of e.g. "annotate --follow --number" should not change without some
deprecation time.
author | Thomas Arendsen Hein <thomas@intevation.de> |
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date | Wed, 03 Mar 2010 22:04:59 +0100 |
parents | d6512b3e9ac0 |
children | 67bb9d78f05e |
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# ancestor.py - generic DAG ancestor algorithm for mercurial # # Copyright 2006 Matt Mackall <mpm@selenic.com> # # This software may be used and distributed according to the terms of the # GNU General Public License version 2 or any later version. import heapq def ancestor(a, b, pfunc): """ return a minimal-distance ancestor of nodes a and b, or None if there is no such ancestor. Note that there can be several ancestors with the same (minimal) distance, and the one returned is arbitrary. pfunc must return a list of parent vertices for a given vertex """ if a == b: return a # find depth from root of all ancestors parentcache = {} visit = [a, b] depth = {} while visit: vertex = visit[-1] pl = pfunc(vertex) parentcache[vertex] = pl if not pl: depth[vertex] = 0 visit.pop() else: for p in pl: if p == a or p == b: # did we find a or b as a parent? return p # we're done if p not in depth: visit.append(p) if visit[-1] == vertex: depth[vertex] = min([depth[p] for p in pl]) - 1 visit.pop() # traverse ancestors in order of decreasing distance from root def ancestors(vertex): h = [(depth[vertex], vertex)] seen = set() while h: d, n = heapq.heappop(h) if n not in seen: seen.add(n) yield (d, n) for p in parentcache[n]: heapq.heappush(h, (depth[p], p)) def generations(vertex): sg, s = None, set() for g, v in ancestors(vertex): if g != sg: if sg: yield sg, s sg, s = g, set((v,)) else: s.add(v) yield sg, s x = generations(a) y = generations(b) gx = x.next() gy = y.next() # increment each ancestor list until it is closer to root than # the other, or they match try: while 1: if gx[0] == gy[0]: for v in gx[1]: if v in gy[1]: return v gy = y.next() gx = x.next() elif gx[0] > gy[0]: gy = y.next() else: gx = x.next() except StopIteration: return None