Mercurial > hg
view mercurial/bdiff.c @ 33475:f501322512b6
parsers: fix invariant bug in find_deepest (issue5623)
find_deepest is used to find the "best" ancestors given a list. In the main
loop it keeps an invariant called 'ninteresting' which is supposed to contain
the number of non-zero entries in the 'interesting' array. This invariant is
incorrectly maintained, however, which leads the the algorithm returning an
empty result for certain graphs. This has been fixed.
Also, the 'interesting' array is supposed to fit 2^ancestors values, but is
incorrectly allocated to twice that size. This has been fixed as well.
The tests in test-ancestor.py compare the Python and C versions of the code,
and report the error correctly, since the Python version works correct. Even
so, I have added an additional test against the expected result, in the event
that both algorithms have an identical error in the future.
This fixes issue5623.
author | Sune Foldager <cryo@cyanite.org> |
---|---|
date | Fri, 14 Jul 2017 13:48:17 +0200 |
parents | d195fa651b51 |
children | ff4c9c6263de |
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/* bdiff.c - efficient binary diff extension for Mercurial Copyright 2005, 2006 Matt Mackall <mpm@selenic.com> This software may be used and distributed according to the terms of the GNU General Public License, incorporated herein by reference. Based roughly on Python difflib */ #include <stdlib.h> #include <string.h> #include <limits.h> #include "compat.h" #include "bitmanipulation.h" #include "bdiff.h" /* Hash implementation from diffutils */ #define ROL(v, n) ((v) << (n) | (v) >> (sizeof(v) * CHAR_BIT - (n))) #define HASH(h, c) ((c) + ROL(h ,7)) struct pos { int pos, len; }; int bdiff_splitlines(const char *a, ssize_t len, struct bdiff_line **lr) { unsigned hash; int i; const char *p, *b = a; const char * const plast = a + len - 1; struct bdiff_line *l; /* count the lines */ i = 1; /* extra line for sentinel */ for (p = a; p < plast; p++) if (*p == '\n') i++; if (p == plast) i++; *lr = l = (struct bdiff_line *)malloc(sizeof(struct bdiff_line) * i); if (!l) return -1; /* build the line array and calculate hashes */ hash = 0; for (p = a; p < plast; p++) { hash = HASH(hash, *p); if (*p == '\n') { l->hash = hash; hash = 0; l->len = p - b + 1; l->l = b; l->n = INT_MAX; l++; b = p + 1; } } if (p == plast) { hash = HASH(hash, *p); l->hash = hash; l->len = p - b + 1; l->l = b; l->n = INT_MAX; l++; } /* set up a sentinel */ l->hash = 0; l->len = 0; l->l = a + len; return i - 1; } static inline int cmp(struct bdiff_line *a, struct bdiff_line *b) { return a->hash != b->hash || a->len != b->len || memcmp(a->l, b->l, a->len); } static int equatelines(struct bdiff_line *a, int an, struct bdiff_line *b, int bn) { int i, j, buckets = 1, t, scale; struct pos *h = NULL; /* build a hash table of the next highest power of 2 */ while (buckets < bn + 1) buckets *= 2; /* try to allocate a large hash table to avoid collisions */ for (scale = 4; scale; scale /= 2) { h = (struct pos *)malloc(scale * buckets * sizeof(struct pos)); if (h) break; } if (!h) return 0; buckets = buckets * scale - 1; /* clear the hash table */ for (i = 0; i <= buckets; i++) { h[i].pos = -1; h[i].len = 0; } /* add lines to the hash table chains */ for (i = 0; i < bn; i++) { /* find the equivalence class */ for (j = b[i].hash & buckets; h[j].pos != -1; j = (j + 1) & buckets) if (!cmp(b + i, b + h[j].pos)) break; /* add to the head of the equivalence class */ b[i].n = h[j].pos; b[i].e = j; h[j].pos = i; h[j].len++; /* keep track of popularity */ } /* compute popularity threshold */ t = (bn >= 31000) ? bn / 1000 : 1000000 / (bn + 1); /* match items in a to their equivalence class in b */ for (i = 0; i < an; i++) { /* find the equivalence class */ for (j = a[i].hash & buckets; h[j].pos != -1; j = (j + 1) & buckets) if (!cmp(a + i, b + h[j].pos)) break; a[i].e = j; /* use equivalence class for quick compare */ if (h[j].len <= t) a[i].n = h[j].pos; /* point to head of match list */ else a[i].n = -1; /* too popular */ } /* discard hash tables */ free(h); return 1; } static int longest_match(struct bdiff_line *a, struct bdiff_line *b, struct pos *pos, int a1, int a2, int b1, int b2, int *omi, int *omj) { int mi = a1, mj = b1, mk = 0, i, j, k, half, bhalf; /* window our search on large regions to better bound worst-case performance. by choosing a window at the end, we reduce skipping overhead on the b chains. */ if (a2 - a1 > 30000) a1 = a2 - 30000; half = (a1 + a2 - 1) / 2; bhalf = (b1 + b2 - 1) / 2; for (i = a1; i < a2; i++) { /* skip all lines in b after the current block */ for (j = a[i].n; j >= b2; j = b[j].n) ; /* loop through all lines match a[i] in b */ for (; j >= b1; j = b[j].n) { /* does this extend an earlier match? */ for (k = 1; j - k >= b1 && i - k >= a1; k++) { /* reached an earlier match? */ if (pos[j - k].pos == i - k) { k += pos[j - k].len; break; } /* previous line mismatch? */ if (a[i - k].e != b[j - k].e) break; } pos[j].pos = i; pos[j].len = k; /* best match so far? we prefer matches closer to the middle to balance recursion */ if (k > mk) { /* a longer match */ mi = i; mj = j; mk = k; } else if (k == mk) { if (i > mi && i <= half && j > b1) { /* same match but closer to half */ mi = i; mj = j; } else if (i == mi && (mj > bhalf || i == a1)) { /* same i but best earlier j */ mj = j; } } } } if (mk) { mi = mi - mk + 1; mj = mj - mk + 1; } /* expand match to include subsequent popular lines */ while (mi + mk < a2 && mj + mk < b2 && a[mi + mk].e == b[mj + mk].e) mk++; *omi = mi; *omj = mj; return mk; } static struct bdiff_hunk *recurse(struct bdiff_line *a, struct bdiff_line *b, struct pos *pos, int a1, int a2, int b1, int b2, struct bdiff_hunk *l) { int i, j, k; while (1) { /* find the longest match in this chunk */ k = longest_match(a, b, pos, a1, a2, b1, b2, &i, &j); if (!k) return l; /* and recurse on the remaining chunks on either side */ l = recurse(a, b, pos, a1, i, b1, j, l); if (!l) return NULL; l->next = (struct bdiff_hunk *)malloc(sizeof(struct bdiff_hunk)); if (!l->next) return NULL; l = l->next; l->a1 = i; l->a2 = i + k; l->b1 = j; l->b2 = j + k; l->next = NULL; /* tail-recursion didn't happen, so do equivalent iteration */ a1 = i + k; b1 = j + k; } } int bdiff_diff(struct bdiff_line *a, int an, struct bdiff_line *b, int bn, struct bdiff_hunk *base) { struct bdiff_hunk *curr; struct pos *pos; int t, count = 0; /* allocate and fill arrays */ t = equatelines(a, an, b, bn); pos = (struct pos *)calloc(bn ? bn : 1, sizeof(struct pos)); if (pos && t) { /* generate the matching block list */ curr = recurse(a, b, pos, 0, an, 0, bn, base); if (!curr) return -1; /* sentinel end hunk */ curr->next = (struct bdiff_hunk *)malloc(sizeof(struct bdiff_hunk)); if (!curr->next) return -1; curr = curr->next; curr->a1 = curr->a2 = an; curr->b1 = curr->b2 = bn; curr->next = NULL; } free(pos); /* normalize the hunk list, try to push each hunk towards the end */ for (curr = base->next; curr; curr = curr->next) { struct bdiff_hunk *next = curr->next; if (!next) break; if (curr->a2 == next->a1 || curr->b2 == next->b1) while (curr->a2 < an && curr->b2 < bn && next->a1 < next->a2 && next->b1 < next->b2 && !cmp(a + curr->a2, b + curr->b2)) { curr->a2++; next->a1++; curr->b2++; next->b1++; } } for (curr = base->next; curr; curr = curr->next) count++; return count; } void bdiff_freehunks(struct bdiff_hunk *l) { struct bdiff_hunk *n; for (; l; l = n) { n = l->next; free(l); } }