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verify: explicitly return 0 if no error are encountered
authorPierre-Yves David <pierre-yves.david@octobus.net>
Wed, 06 Mar 2019 11:38:54 +0100
changeset 41868 567892b4306c
parent 41867 e8c4a9f5b986
child 41869 4da2261e949b
verify: explicitly return 0 if no error are encountered Relying on the fact None is treated as 0 by other logics seems smarter than we should be.
mercurial/verify.py file | annotate | diff | comparison | revisions 
--- a/mercurial/verify.py	Wed Mar 06 11:35:34 2019 +0100
+++ b/mercurial/verify.py	Wed Mar 06 11:38:54 2019 +0100
@@ -134,7 +134,7 @@
 
         This method run all verifications, displaying issues as they are found.
 
-        return 1 if any error have been encountered"""
+        return 1 if any error have been encountered, 0 otherwise."""
         repo = self.repo
 
         ui = repo.ui
@@ -171,6 +171,7 @@
                 ui.warn(_("(first damaged changeset appears to be %d)\n")
                         % min(self.badrevs))
             return 1
+        return 0
 
     def _verifychangelog(self):
         ui = self.ui
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