py3: make regular expressions bytes by prepending b''
Regexes start with r'' and hence transformer skips adding b'' there.
# skip-blame because we are just adding b''
Differential Revision: https://phab.mercurial-scm.org/D1794
--- a/mercurial/byterange.py Fri Dec 29 05:27:00 2017 +0530
+++ b/mercurial/byterange.py Fri Dec 29 05:28:05 2017 +0530
@@ -416,7 +416,7 @@
if range_header is None:
return None
if _rangere is None:
- _rangere = re.compile(r'^bytes=(\d{1,})-(\d*)')
+ _rangere = re.compile(br'^bytes=(\d{1,})-(\d*)')
match = _rangere.match(range_header)
if match:
tup = range_tuple_normalize(match.group(1, 2))
--- a/mercurial/mdiff.py Fri Dec 29 05:27:00 2017 +0530
+++ b/mercurial/mdiff.py Fri Dec 29 05:28:05 2017 +0530
@@ -100,7 +100,7 @@
if blank and opts.ignoreblanklines:
text = re.sub('\n+', '\n', text).strip('\n')
if opts.ignorewseol:
- text = re.sub(r'[ \t\r\f]+\n', r'\n', text)
+ text = re.sub(br'[ \t\r\f]+\n', r'\n', text)
return text
def splitblock(base1, lines1, base2, lines2, opts):