changeset 25549:f93ff3ab8d14

revset: mark spots that should use 'smartset.min()' Using smartset's min will be significantly faster when the input set can provided an optimised answer. I do not have time to fix all of them but I'm marking the spot.
author Pierre-Yves David <pierre-yves.david@fb.com>
date Thu, 11 Jun 2015 14:26:44 -0700
parents 9584bcf27637
children 3e9049876ace
files mercurial/revset.py
diffstat 1 files changed, 8 insertions(+), 0 deletions(-) [+]
line wrap: on
line diff
--- a/mercurial/revset.py	Thu Jun 11 14:21:21 2015 -0700
+++ b/mercurial/revset.py	Thu Jun 11 14:26:44 2015 -0700
@@ -58,6 +58,8 @@
 
     def iterate():
         cl = repo.changelog
+        # XXX this should be 'parentset.min()' assuming 'parentset' is a
+        # smartset (and if it is not, it should.)
         first = min(revs)
         nullrev = node.nullrev
         if first == nullrev:
@@ -85,6 +87,8 @@
     visit = list(heads)
     reachable = set()
     seen = {}
+    # XXX this should be 'parentset.min()' assuming 'parentset' is a smartset
+    # (and if it is not, it should.)
     minroot = min(roots)
     roots = set(roots)
     # open-code the post-order traversal due to the tiny size of
@@ -614,6 +618,8 @@
     if not parentset:
         return baseset(cs)
     pr = repo.changelog.parentrevs
+    # XXX this should be 'parentset.min()' assuming 'parentset' is a smartset
+    # (and if it is not, it should.)
     minrev = min(parentset)
     for r in narrow:
         if r <= minrev:
@@ -1217,6 +1223,8 @@
     cl = repo.changelog
     if not subset:
         return baseset()
+    # XXX this should be 'parentset.min()' assuming 'parentset' is a smartset
+    # (and if it is not, it should.)
     baserev = min(subset)
     parentscount = [0]*(len(repo) - baserev)
     for r in cl.revs(start=baserev + 1):